16v^2-70v+49=0

Solution for 16v^2-70v+49=0 equation:

16v^2-70v+49=0

a = 16; b = -70; c = +49;
Δ = b2-4ac
Δ = -702-4·16·49
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-42}{2*16}=\frac{28}{32}
=7/8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+42}{2*16}=\frac{112}{32}
=3+1/2
$